Lesson Focus
This issue practices Solving Linear Equations Review in Algebra II.
Synopsis
A linear equation is an equation in which the variable has a first-degree power, and solving it means finding the value that makes the equation true. The central principle is to preserve equality by performing equivalent operations on both sides. Depending on the equation, you may simplify expressions, use the distributive property, combine like terms, and apply inverse operations to isolate the variable.
In this issue, you review solving one-step and multi-step linear equations. You work carefully through each transformation and can check a solution by substituting it back into the original equation. These equation-solving habits are essential in Algebra II, where linear techniques are frequently used inside more complex problems involving formulas, systems, functions, inequalities, and nonlinear equations.
Practice Problems
Problem 1. Solve \(x + 7 = 15\).
A. \(x = 6\)
B. \(x = 7\)
C. \(x = 8\)
D. \(x = 9\)
E. \(x = 22\)
Problem 2. Solve \(3x = 21\).
A. \(x = 6\)
B. \(x = 7\)
C. \(x = 8\)
D. \(x = 18\)
E. \(x = 24\)
Problem 3. Solve \(x – 5 = 12\).
A. \(x = 7\)
B. \(x = 12\)
C. \(x = 17\)
D. \(x = 60\)
E. \(x = -7\)
Problem 4. Solve \(x/4 = 9\).
A. \(x = 13\)
B. \(x = 36\)
C. \(x = 5\)
D. \(x = 2.25\)
E. \(x = 45\)
Problem 5. Solve \(2x + 3 = 11\).
A. \(x = 3\)
B. \(x = 4\)
C. \(x = 5\)
D. \(x = 7\)
E. \(x = 8\)
Problem 6. Solve \(5x – 10 = 20\).
A. \(x = 2\)
B. \(x = 4\)
C. \(x = 6\)
D. \(x = 10\)
E. \(x = 30\)
Problem 7. Which step solves \(x – 9 = 14\)?
A. subtract 9
B. add 9
C. multiply by 9
D. divide by 9
E. square both sides
Google Form
Answer Key
- Problem 1: C
- Problem 2: B
- Problem 3: C
- Problem 4: B
- Problem 5: B
- Problem 6: C
- Problem 7: B